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576=x^2+14x
We move all terms to the left:
576-(x^2+14x)=0
We get rid of parentheses
-x^2-14x+576=0
We add all the numbers together, and all the variables
-1x^2-14x+576=0
a = -1; b = -14; c = +576;
Δ = b2-4ac
Δ = -142-4·(-1)·576
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-50}{2*-1}=\frac{-36}{-2} =+18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+50}{2*-1}=\frac{64}{-2} =-32 $
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